No.105248
作者：yenongqing
邮件：yenongqing@163.com
ID：76232
登陆：2次
文章数：3篇
最后登陆IP：125.76.157.10
最后登陆：2007/8/11 15:47:18
注册：2007/4/27 14:25:43
财富：116
发帖时间：2007/4/27 14:27:57
发贴者IP：222.90.17.64
标题：yenongqing:串口求助
摘要：No.105248串口求助 做串口通讯时 有个问题向大家请教：
写了一个接受中断函数
void getchar() interrupt 4 using 3
{
u_char i=0 ;
EA=0;
if(RI==1)
{
temp=SBUF; RecCharString[i]=temp; i++;RI=0;
}
if(i==8)
{ P3_4=1;
if( RecCharString[0]==0x5e)
{
if( RecCharString[1]==0xb0)//心跳
{
if( RecCharString[2]==0x00)
{
if(RecCharString[3]==0x04)
{
if(RecCharString[4]==0x00)
{
if(RecCharString[5]==0x00)
{
if(RecCharString[6]==0x01)
{
if(RecCharString[7]==0x12)
{
Xintiao=1;i=0;
}
}
}
}
}
}
}
}
} EA=1;
}
结果整个程序单片机无法执行
去掉这个中断函数
其他的程序都可以执行
整个程序：
#include <reg51.h>
#define u_char unsigned char
#define u_int unsigned int
#define StringWidth 4
sbit P2_7=P2^7;
sbit P2_6=P2^6;
sbit P2_5=P2^5;
sbit P2_4=P2^4;
sbit P2_2=P2^2;
sbit P2_1=P2^1;
sbit P2_0=P2^0;
sbit P3_6=P3^6;
sbit P3_5=P3^5;
sbit P3_4=P3^4;
u_char temp; u_int ui;
u_char data SendCharString[StringWidth]={0x5e,0x03,0x00,0x04};
u_char data yangan[17]={0x5e,0x11,0x00,0x11,0x99,0x99,0x99,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};
u_char data fanyangan[17]={0x5e,0x12,0x00,0x11,0x99,0x99,0x99,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};
u_char data hongwai[4]={0x5e,0x13,0x00,0x04};
u_char data fanhongwai[4]={0x5e,0x14,0x00,0x04};
u_char data DString[9]={0x5e,0x80,0x00,0x09,0x51,0x52,0x53,0x54,0x55};
u_char data RecCharString[8],CheckSum[StringWidth];
u_char data k,ro,d,f,flag=0,count=0,wanglo=0,Xintiao=0;
u_char data kaiguan0=1,kaiguan1=1;
u_char data fankaiguan0=1,fankaiguan1=1;
u_char data xintiaozhi[11]={0x5e,0x10,0x00,0x0b,0x99,0x99,0x99,0x00,0x00,0x00,0x00}; void delay1ms(void)
{
u_char data i;
for(i=0;i <=250;i++)
{;;}
} void delay10ms(void)
{
u_char data j;
for(j=0;j <=10;j++)
{delay1ms();}
}
void send_char(u_char ch)
{
EA=0;
SBUF=ch;
while(TI==0);
TI=0;
EA=1;
}
void send_string(u_char *str, u_char strlen)
{
u_int k;
for(k=0;k <strlen;k++)
send_char(*(str + k)) ;
} void JSCheckSum(u_char *str, u_char strlen)
{
u_char i;
u_int chushu=0,chushu1=0,chushu2=0,chushu3=0, sum=0;
for(i=0;i <strlen;i++)
sum=sum+str[i]; ......
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